7 2019-10-28  Ö-Rallye im WBB
Romana Mechail - Judith Adler
   

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Paar: 7    Romana Mechail - Judith Adler

Score: 74    44,0 %    Platz: 6    
                              
Rnd  Tisch  Als  Geg  Board  Kont     Aus  Ergebnis  Score    %    Runde    %    Ges      %        Name d. Gegners

 1     3    O-W   2     21   2K  O -1 TB     50          4   67                                    Mutz - Mutz
                        22   6H  S  = KA    980          0    0                                             
                        23   2Px O -2 HA    500          0    0                                             
                        24   2H  N +1 T6    140          0    0        4   17      4   16,7                 

 2     2    O-W   4     17   3H  N  = KA    140          4   67                                    Kosicek - Kosicek
                        18   3N  W  = H5       -400      0    0                                             
                        19   3N  N -1 P4        -50      5   83                                             
                        20   2P  O +1 KA       -140      0    0        9   38     13   27,1                 

 3     4    N-S   6     5    2N  S  = P2    120          4   67                                    Adam - Radl
                        6    2T  O +1 H3       -110      2   33                                             
                        7    3N  W +1 T4       -630      1   17                                             
                        8    3P  O  = PD       -140      6  100       13   54     26   36,1                 

 4     4    O-W   1     9    5T  S  = T10   400          1   17                                    Weiss - Schneider
                        10   3N  N +4 PB    720          0    0                                             
                        11   1T  S +4 K8    150          4   67                                             
                        12   1H  O -1 KA     50          4   67        9   38     35   36,5                 

 5     2    N-S   3     1    4H  O -1 KA     50          3   50                                    Wasser - Pendl
                        2    3T  W  = K3       -110      2   33                                             
                        3    3N  S -1 P7        -50      2   33                                             
                        4    4P  W +2 H5       -680      0    0        7   29     42   35,0                 

 6     3    N-S   5     13   3P  O +2 HA       -200      1   17                                    Hochstöger - Lindenthal
                        14   2T  N +1 KA    110          2   33                                             
                        15   3N  W -1 PK     50          6  100                                             
                        16   2T  S +3 K2    150          2   33       11   46     53   36,8                 

 7     1    O-W   8     25   2P  O  = HA       -110      6  100                                    Fuhrmann - Bek-Areschew
                        26   3H  N  = K5    140          4   67                                             
                        27   2P  W +2 HB       -170      6  100                                             
                        28   3N  W +1 PD       -430      5   83       21   88     74   44,0                 


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